Adam has 66 stickers.
After
25 of the green stickers is given away and
another 30 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
5 u |
3 u - 30 |
Change |
- 2 u |
+ 30 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
25 =
35 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 5 u + 3 u - 30
= 8 u - 30
8 u - 30 = 66
8 u = 66 + 30
8 u = 96
1 u = 96 ÷ 8 = 12
Number of green stickers in the end
= 3 u
= 3 x 12
= 36
(b)
Number of less blue stickers than green stickers at first
= 5 u - (3 u - 30)
= 5 u - 3 u + 30
= 2 u + 30
= 2 x 12 + 30
= 24 + 30
= 54
(c)
Number of green stickers given away
= 2 u
= 2 x 12
= 24
Answer(s): (a) 36; (b) 54; (c) 24