Adam has 106 stickers.
After
35 of the red stickers is given away and
another 27 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
5 u |
2 u - 27 |
Change |
- 3 u |
+ 27 |
After |
2 u |
2 u |
(a)
Fraction of the red stickers left
= 1 -
35 =
25 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 27
= 7 u - 27
7 u - 27 = 106
7 u = 106 + 27
7 u = 133
1 u = 133 ÷ 7 = 19
Number of red stickers in the end
= 2 u
= 2 x 19
= 38
(b)
Number of less green stickers than red stickers at first
= 5 u - (2 u - 27)
= 5 u - 2 u + 27
= 3 u + 27
= 3 x 19 + 27
= 57 + 27
= 84
(c)
Number of red stickers given away
= 3 u
= 3 x 19
= 57
Answer(s): (a) 38; (b) 84; (c) 57