Adam has 131 stickers.
After
59 of the red stickers is given away and
another 12 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
9 u |
4 u - 12 |
Change |
- 5 u |
+ 12 |
After |
4 u |
4 u |
(a)
Fraction of the red stickers left
= 1 -
59 =
49 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 12
= 13 u - 12
13 u - 12 = 131
13 u = 131 + 12
13 u = 143
1 u = 143 ÷ 13 = 11
Number of red stickers in the end
= 4 u
= 4 x 11
= 44
(b)
Number of less green stickers than red stickers at first
= 9 u - (4 u - 12)
= 9 u - 4 u + 12
= 5 u + 12
= 5 x 11 + 12
= 55 + 12
= 67
(c)
Number of red stickers given away
= 5 u
= 5 x 11
= 55
Answer(s): (a) 44; (b) 67; (c) 55