Adam has 141 stickers.
After
25 of the red stickers is given away and
another 27 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
5 u |
3 u - 27 |
Change |
- 2 u |
+ 27 |
After |
3 u |
3 u |
(a)
Fraction of the red stickers left
= 1 -
25 =
35 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 5 u + 3 u - 27
= 8 u - 27
8 u - 27 = 141
8 u = 141 + 27
8 u = 168
1 u = 168 ÷ 8 = 21
Number of red stickers in the end
= 3 u
= 3 x 21
= 63
(b)
Number of less green stickers than red stickers at first
= 5 u - (3 u - 27)
= 5 u - 3 u + 27
= 2 u + 27
= 2 x 21 + 27
= 42 + 27
= 69
(c)
Number of red stickers given away
= 2 u
= 2 x 21
= 42
Answer(s): (a) 63; (b) 69; (c) 42