Adam has 163 stickers.
After
37 of the green stickers is given away and
another 13 red stickers are bought,
there is an equal number of green and red stickers.
- How many green stickers are there in the end?
- How many less red stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Red |
Before |
7 u |
4 u - 13 |
Change |
- 3 u |
+ 13 |
After |
4 u |
4 u |
(a)
Fraction of the green stickers left
= 1 -
37 =
47 The number of green stickers and red stickers in the end is the same.
Total number of stickers at first
= 7 u + 4 u - 13
= 11 u - 13
11 u - 13 = 163
11 u = 163 + 13
11 u = 176
1 u = 176 ÷ 11 = 16
Number of green stickers in the end
= 4 u
= 4 x 16
= 64
(b)
Number of less red stickers than green stickers at first
= 7 u - (4 u - 13)
= 7 u - 4 u + 13
= 3 u + 13
= 3 x 16 + 13
= 48 + 13
= 61
(c)
Number of green stickers given away
= 3 u
= 3 x 16
= 48
Answer(s): (a) 64; (b) 61; (c) 48