Adam has 181 stickers.
After
59 of the blue stickers is given away and
another 40 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
9 u |
4 u - 40 |
Change |
- 5 u |
+ 40 |
After |
4 u |
4 u |
(a)
Fraction of the blue stickers left
= 1 -
59 =
49 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 40
= 13 u - 40
13 u - 40 = 181
13 u = 181 + 40
13 u = 221
1 u = 221 ÷ 13 = 17
Number of blue stickers in the end
= 4 u
= 4 x 17
= 68
(b)
Number of less green stickers than blue stickers at first
= 9 u - (4 u - 40)
= 9 u - 4 u + 40
= 5 u + 40
= 5 x 17 + 40
= 85 + 40
= 125
(c)
Number of blue stickers given away
= 5 u
= 5 x 17
= 85
Answer(s): (a) 68; (b) 125; (c) 85