Adam has 192 stickers.
After
35 of the green stickers is given away and
another 39 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
5 u |
2 u - 39 |
Change |
- 3 u |
+ 39 |
After |
2 u |
2 u |
(a)
Fraction of the green stickers left
= 1 -
35 =
25 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 39
= 7 u - 39
7 u - 39 = 192
7 u = 192 + 39
7 u = 231
1 u = 231 ÷ 7 = 33
Number of green stickers in the end
= 2 u
= 2 x 33
= 66
(b)
Number of less blue stickers than green stickers at first
= 5 u - (2 u - 39)
= 5 u - 2 u + 39
= 3 u + 39
= 3 x 33 + 39
= 99 + 39
= 138
(c)
Number of green stickers given away
= 3 u
= 3 x 33
= 99
Answer(s): (a) 66; (b) 138; (c) 99