Adam has 104 stickers.
After
49 of the green stickers is given away and
another 36 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
9 u |
5 u - 36 |
Change |
- 4 u |
+ 36 |
After |
5 u |
5 u |
(a)
Fraction of the green stickers left
= 1 -
49 =
59 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 36
= 14 u - 36
14 u - 36 = 104
14 u = 104 + 36
14 u = 140
1 u = 140 ÷ 14 = 10
Number of green stickers in the end
= 5 u
= 5 x 10
= 50
(b)
Number of less blue stickers than green stickers at first
= 9 u - (5 u - 36)
= 9 u - 5 u + 36
= 4 u + 36
= 4 x 10 + 36
= 40 + 36
= 76
(c)
Number of green stickers given away
= 4 u
= 4 x 10
= 40
Answer(s): (a) 50; (b) 76; (c) 40