Adam has 56 stickers.
After
59 of the green stickers is given away and
another 22 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
9 u |
4 u - 22 |
Change |
- 5 u |
+ 22 |
After |
4 u |
4 u |
(a)
Fraction of the green stickers left
= 1 -
59 =
49 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 9 u + 4 u - 22
= 13 u - 22
13 u - 22 = 56
13 u = 56 + 22
13 u = 78
1 u = 78 ÷ 13 = 6
Number of green stickers in the end
= 4 u
= 4 x 6
= 24
(b)
Number of less blue stickers than green stickers at first
= 9 u - (4 u - 22)
= 9 u - 4 u + 22
= 5 u + 22
= 5 x 6 + 22
= 30 + 22
= 52
(c)
Number of green stickers given away
= 5 u
= 5 x 6
= 30
Answer(s): (a) 24; (b) 52; (c) 30