Adam has 73 stickers.
After
49 of the red stickers is given away and
another 11 blue stickers are bought,
there is an equal number of red and blue stickers.
- How many red stickers are there in the end?
- How many less blue stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Blue |
Before |
9 u |
5 u - 11 |
Change |
- 4 u |
+ 11 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
49 =
59 The number of red stickers and blue stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 11
= 14 u - 11
14 u - 11 = 73
14 u = 73 + 11
14 u = 84
1 u = 84 ÷ 14 = 6
Number of red stickers in the end
= 5 u
= 5 x 6
= 30
(b)
Number of less blue stickers than red stickers at first
= 9 u - (5 u - 11)
= 9 u - 5 u + 11
= 4 u + 11
= 4 x 6 + 11
= 24 + 11
= 35
(c)
Number of red stickers given away
= 4 u
= 4 x 6
= 24
Answer(s): (a) 30; (b) 35; (c) 24