Adam has 130 stickers.
After
58 of the green stickers is given away and
another 24 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
8 u |
3 u - 24 |
Change |
- 5 u |
+ 24 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
58 =
38 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 8 u + 3 u - 24
= 11 u - 24
11 u - 24 = 130
11 u = 130 + 24
11 u = 154
1 u = 154 ÷ 11 = 14
Number of green stickers in the end
= 3 u
= 3 x 14
= 42
(b)
Number of less blue stickers than green stickers at first
= 8 u - (3 u - 24)
= 8 u - 3 u + 24
= 5 u + 24
= 5 x 14 + 24
= 70 + 24
= 94
(c)
Number of green stickers given away
= 5 u
= 5 x 14
= 70
Answer(s): (a) 42; (b) 94; (c) 70