Adam has 153 stickers.
After
47 of the green stickers is given away and
another 7 blue stickers are bought,
there is an equal number of green and blue stickers.
- How many green stickers are there in the end?
- How many less blue stickers than green stickers are there at first?
- How many green stickers are given away?
|
Green |
Blue |
Before |
7 u |
3 u - 7 |
Change |
- 4 u |
+ 7 |
After |
3 u |
3 u |
(a)
Fraction of the green stickers left
= 1 -
47 =
37 The number of green stickers and blue stickers in the end is the same.
Total number of stickers at first
= 7 u + 3 u - 7
= 10 u - 7
10 u - 7 = 153
10 u = 153 + 7
10 u = 160
1 u = 160 ÷ 10 = 16
Number of green stickers in the end
= 3 u
= 3 x 16
= 48
(b)
Number of less blue stickers than green stickers at first
= 7 u - (3 u - 7)
= 7 u - 3 u + 7
= 4 u + 7
= 4 x 16 + 7
= 64 + 7
= 71
(c)
Number of green stickers given away
= 4 u
= 4 x 16
= 64
Answer(s): (a) 48; (b) 71; (c) 64