Adam has 171 stickers.
After
35 of the blue stickers is given away and
another 46 red stickers are bought,
there is an equal number of blue and red stickers.
- How many blue stickers are there in the end?
- How many less red stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Red |
Before |
5 u |
2 u - 46 |
Change |
- 3 u |
+ 46 |
After |
2 u |
2 u |
(a)
Fraction of the blue stickers left
= 1 -
35 =
25 The number of blue stickers and red stickers in the end is the same.
Total number of stickers at first
= 5 u + 2 u - 46
= 7 u - 46
7 u - 46 = 171
7 u = 171 + 46
7 u = 217
1 u = 217 ÷ 7 = 31
Number of blue stickers in the end
= 2 u
= 2 x 31
= 62
(b)
Number of less red stickers than blue stickers at first
= 5 u - (2 u - 46)
= 5 u - 2 u + 46
= 3 u + 46
= 3 x 31 + 46
= 93 + 46
= 139
(c)
Number of blue stickers given away
= 3 u
= 3 x 31
= 93
Answer(s): (a) 62; (b) 139; (c) 93