Adam has 144 stickers.
After
310 of the red stickers is given away and
another 26 blue stickers are bought,
there is an equal number of red and blue stickers.
- How many red stickers are there in the end?
- How many less blue stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Blue |
Before |
10 u |
7 u - 26 |
Change |
- 3 u |
+ 26 |
After |
7 u |
7 u |
(a)
Fraction of the red stickers left
= 1 -
310 =
710 The number of red stickers and blue stickers in the end is the same.
Total number of stickers at first
= 10 u + 7 u - 26
= 17 u - 26
17 u - 26 = 144
17 u = 144 + 26
17 u = 170
1 u = 170 ÷ 17 = 10
Number of red stickers in the end
= 7 u
= 7 x 10
= 70
(b)
Number of less blue stickers than red stickers at first
= 10 u - (7 u - 26)
= 10 u - 7 u + 26
= 3 u + 26
= 3 x 10 + 26
= 30 + 26
= 56
(c)
Number of red stickers given away
= 3 u
= 3 x 10
= 30
Answer(s): (a) 70; (b) 56; (c) 30