Adam has 170 stickers.
After
49 of the red stickers is given away and
another 12 green stickers are bought,
there is an equal number of red and green stickers.
- How many red stickers are there in the end?
- How many less green stickers than red stickers are there at first?
- How many red stickers are given away?
|
Red |
Green |
Before |
9 u |
5 u - 12 |
Change |
- 4 u |
+ 12 |
After |
5 u |
5 u |
(a)
Fraction of the red stickers left
= 1 -
49 =
59 The number of red stickers and green stickers in the end is the same.
Total number of stickers at first
= 9 u + 5 u - 12
= 14 u - 12
14 u - 12 = 170
14 u = 170 + 12
14 u = 182
1 u = 182 ÷ 14 = 13
Number of red stickers in the end
= 5 u
= 5 x 13
= 65
(b)
Number of less green stickers than red stickers at first
= 9 u - (5 u - 12)
= 9 u - 5 u + 12
= 4 u + 12
= 4 x 13 + 12
= 52 + 12
= 64
(c)
Number of red stickers given away
= 4 u
= 4 x 13
= 52
Answer(s): (a) 65; (b) 64; (c) 52