Adam has 198 stickers.
After ⁴₇ of the green stickers is given away and
another 12 blue stickers are bought,
there is an equal number of green and blue stickers.

1. How many green stickers are there in the end?
2. How many less blue stickers than green stickers are there at first?
3. How many green stickers are given away?

	Green	Blue
Before	7 u	3 u - 12
Change	- 4 u	+ 12
After	3 u	3 u

(a)
Fraction of the green stickers left
= 1 - ⁴₇
= ³₇

The number of green stickers and blue stickers in the end is the same.

Total number of stickers at first
= 7 u + 3 u - 12
= 10 u - 12

10 u - 12 = 198
10 u = 198 + 12
10 u = 210

1 u = 210 ÷ 10 = 21

Number of green stickers in the end
= 3 u
= 3 x 21
= 63

(b)
Number of less blue stickers than green stickers at first
= 7 u - (3 u - 12)
= 7 u - 3 u + 12
= 4 u + 12
= 4 x 21 + 12
= 84 + 12
= 96

(c)
Number of green stickers given away
= 4 u
= 4 x 21
= 84

Answer(s): (a) 63; (b) 96; (c) 84