Adam has 140 stickers.
After
38 of the blue stickers is given away and
another 42 red stickers are bought,
there is an equal number of blue and red stickers.
- How many blue stickers are there in the end?
- How many less red stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Red |
Before |
8 u |
5 u - 42 |
Change |
- 3 u |
+ 42 |
After |
5 u |
5 u |
(a)
Fraction of the blue stickers left
= 1 -
38 =
58 The number of blue stickers and red stickers in the end is the same.
Total number of stickers at first
= 8 u + 5 u - 42
= 13 u - 42
13 u - 42 = 140
13 u = 140 + 42
13 u = 182
1 u = 182 ÷ 13 = 14
Number of blue stickers in the end
= 5 u
= 5 x 14
= 70
(b)
Number of less red stickers than blue stickers at first
= 8 u - (5 u - 42)
= 8 u - 5 u + 42
= 3 u + 42
= 3 x 14 + 42
= 42 + 42
= 84
(c)
Number of blue stickers given away
= 3 u
= 3 x 14
= 42
Answer(s): (a) 70; (b) 84; (c) 42