Adam has 177 stickers.
After
57 of the blue stickers is given away and
another 48 green stickers are bought,
there is an equal number of blue and green stickers.
- How many blue stickers are there in the end?
- How many less green stickers than blue stickers are there at first?
- How many blue stickers are given away?
|
Blue |
Green |
Before |
7 u |
2 u - 48 |
Change |
- 5 u |
+ 48 |
After |
2 u |
2 u |
(a)
Fraction of the blue stickers left
= 1 -
57 =
27 The number of blue stickers and green stickers in the end is the same.
Total number of stickers at first
= 7 u + 2 u - 48
= 9 u - 48
9 u - 48 = 177
9 u = 177 + 48
9 u = 225
1 u = 225 ÷ 9 = 25
Number of blue stickers in the end
= 2 u
= 2 x 25
= 50
(b)
Number of less green stickers than blue stickers at first
= 7 u - (2 u - 48)
= 7 u - 2 u + 48
= 5 u + 48
= 5 x 25 + 48
= 125 + 48
= 173
(c)
Number of blue stickers given away
= 5 u
= 5 x 25
= 125
Answer(s): (a) 50; (b) 173; (c) 125