Adam has 154 stickers.
After
23 of the red stickers and
35 of the blue stickers are given away,
there is an equal number of red and blue stickers left.
- How many red stickers are there in the end?
- How many more red stickers are there than blue stickers at first?
- How many blue stickers are given away?
|
Red |
Blue |
Total |
Before |
3 x 2 = 6 u |
5 x 1 = 5 u |
154 |
Change |
- 2 x 2 = - 4 u |
- 3 x 1 = - 3 u |
|
After |
1 x 2 = 2 u |
2 x 1 = 2 u |
|
(a)
Fraction of the red stickers left
= 1 -
23 =
13 Fraction of the blue stickers left
= 1 -
35 =
25 Number of red stickers and blue stickers left is the same.
Make the number of red stickers and blue stickers left the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Total number of stickers
= 6 u + 5 u
= 11 u
11 u = 154
1 u = 154 ÷ 11 = 14
Number of red stickers in the end
= 2 u
= 2 x 14
= 28
(b)
Number of more red stickers than blue stickers at first
= 6 u - 5 u
= 1 u
= 1 x 14
= 14
(c)
Number of blue stickers given away
= 5 u - 2 u
= 3 u
= 3 x 14
= 42
Answer(s): (a) 28; (b) 14; (c) 42