Adam has 342 stickers.
After
23 of the green stickers and
37 of the blue stickers are given away,
there is an equal number of green and blue stickers left.
- How many green stickers are there in the end?
- How many more green stickers are there than blue stickers at first?
- How many blue stickers are given away?
|
Green |
Blue |
Total |
Before |
3 x 4 = 12 u |
7 x 1 = 7 u |
342 |
Change |
- 2 x 4 = - 8 u |
- 3 x 1 = - 3 u |
|
After |
1 x 4 = 4 u |
4 x 1 = 4 u |
|
(a)
Fraction of the green stickers left
= 1 -
23 =
13 Fraction of the blue stickers left
= 1 -
37 =
47 Number of green stickers and blue stickers left is the same.
Make the number of green stickers and blue stickers left the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Total number of stickers
= 12 u + 7 u
= 19 u
19 u = 342
1 u = 342 ÷ 19 = 18
Number of green stickers in the end
= 4 u
= 4 x 18
= 72
(b)
Number of more green stickers than blue stickers at first
= 12 u - 7 u
= 5 u
= 5 x 18
= 90
(c)
Number of blue stickers given away
= 7 u - 4 u
= 3 u
= 3 x 18
= 54
Answer(s): (a) 72; (b) 90; (c) 54