Adam has 252 stickers.
After
23 of the green stickers and
25 of the red stickers are given away,
there is an equal number of green and red stickers left.
- How many green stickers are there in the end?
- How many more green stickers are there than red stickers at first?
- How many red stickers are given away?
|
Green |
Red |
Total |
Before |
3 x 3 = 9 u |
5 x 1 = 5 u |
252 |
Change |
- 2 x 3 = - 6 u |
- 2 x 1 = - 2 u |
|
After |
1 x 3 = 3 u |
3 x 1 = 3 u |
|
(a)
Fraction of the green stickers left
= 1 -
23 =
13 Fraction of the red stickers left
= 1 -
25 =
35 Number of green stickers and red stickers left is the same.
Make the number of green stickers and red stickers left the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
Total number of stickers
= 9 u + 5 u
= 14 u
14 u = 252
1 u = 252 ÷ 14 = 18
Number of green stickers in the end
= 3 u
= 3 x 18
= 54
(b)
Number of more green stickers than red stickers at first
= 9 u - 5 u
= 4 u
= 4 x 18
= 72
(c)
Number of red stickers given away
= 5 u - 3 u
= 2 u
= 2 x 18
= 36
Answer(s): (a) 54; (b) 72; (c) 36