Adam has 286 stickers.
After
23 of the blue stickers and
35 of the green stickers are given away,
there is an equal number of blue and green stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers are there than green stickers at first?
- How many green stickers are given away?
|
Blue |
Green |
Total |
Before |
3 x 2 = 6 u |
5 x 1 = 5 u |
286 |
Change |
- 2 x 2 = - 4 u |
- 3 x 1 = - 3 u |
|
After |
1 x 2 = 2 u |
2 x 1 = 2 u |
|
(a)
Fraction of the blue stickers left
= 1 -
23 =
13 Fraction of the green stickers left
= 1 -
35 =
25 Number of blue stickers and green stickers left is the same.
Make the number of blue stickers and green stickers left the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Total number of stickers
= 6 u + 5 u
= 11 u
11 u = 286
1 u = 286 ÷ 11 = 26
Number of blue stickers in the end
= 2 u
= 2 x 26
= 52
(b)
Number of more blue stickers than green stickers at first
= 6 u - 5 u
= 1 u
= 1 x 26
= 26
(c)
Number of green stickers given away
= 5 u - 2 u
= 3 u
= 3 x 26
= 78
Answer(s): (a) 52; (b) 26; (c) 78