Adam has 66 stickers.
After ²₃ of the blue stickers and
³₅ of the red stickers are given away,
there is an equal number of blue and red stickers left.

1. How many blue stickers are there in the end?
2. How many more blue stickers are there than red stickers at first?
3. How many red stickers are given away?

	Blue	Red	Total
Before	3 x 2 = 6 u	5 x 1 = 5 u	66
Change	- 2 x 2 = - 4 u	- 3 x 1 = - 3 u
After	1 x 2 = 2 u	2 x 1 = 2 u

(a)
Fraction of the blue stickers left
= 1 - ²₃
= ¹₃

Fraction of the red stickers left
= 1 - ³₅
= ²₅

Number of blue stickers and red stickers left is the same.
Make the number of blue stickers and red stickers left the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2

Total number of stickers
= 6 u + 5 u
= 11 u

11 u = 66

1 u = 66 ÷ 11 = 6

Number of blue stickers in the end
= 2 u
= 2 x 6
= 12

(b)
Number of more blue stickers than red stickers at first
= 6 u - 5 u
= 1 u
= 1 x 6
= 6

(c)
Number of red stickers given away
= 5 u - 2 u
= 3 u
= 3 x 6
= 18

Answer(s): (a) 12; (b) 6; (c) 18