Adam has 330 stickers.
After ²₃ of the green stickers and
²₇ of the red stickers are given away,
there is an equal number of green and red stickers left.

1. How many green stickers are there in the end?
2. How many more green stickers are there than red stickers at first?
3. How many red stickers are given away?

	Green	Red	Total
Before	3 x 5 = 15 u	7 x 1 = 7 u	330
Change	- 2 x 5 = - 10 u	- 2 x 1 = - 2 u
After	1 x 5 = 5 u	5 x 1 = 5 u

(a)
Fraction of the green stickers left
= 1 - ²₃
= ¹₃

Fraction of the red stickers left
= 1 - ²₇
= ⁵₇

Number of green stickers and red stickers left is the same.
Make the number of green stickers and red stickers left the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5

Total number of stickers
= 15 u + 7 u
= 22 u

22 u = 330

1 u = 330 ÷ 22 = 15

Number of green stickers in the end
= 5 u
= 5 x 15
= 75

(b)
Number of more green stickers than red stickers at first
= 15 u - 7 u
= 8 u
= 8 x 15
= 120

(c)
Number of red stickers given away
= 7 u - 5 u
= 2 u
= 2 x 15
= 30

Answer(s): (a) 75; (b) 120; (c) 30