Adam has 342 stickers.
After ¹₃ of the red stickers and
²₅ of the blue stickers are given away,
there is an equal number of red and blue stickers left.

1. How many red stickers are there in the end?
2. How many more blue stickers are there than red stickers at first?
3. How many blue stickers are given away?

	Red	Blue	Total
Before	3 x 3 = 9 u	5 x 2 = 10 u	342
Change	- 1 x 3 = - 3 u	- 2 x 2 = - 4 u
After	2 x 3 = 6 u	3 x 2 = 6 u

(a)
Fraction of the red stickers left
= 1 - ¹₃
= ²₃

Fraction of the blue stickers left
= 1 - ²₅
= ³₅

Number of red stickers and blue stickers left is the same.
Make the number of red stickers and blue stickers left the same using the LCM of 2 and 3.
LCM of 2 and 3 = 6

Total number of stickers
= 9 u + 10 u
= 19 u

19 u = 342

1 u = 342 ÷ 19 = 18

Number of red stickers in the end
= 6 u
= 6 x 18
= 108

(b)
Number of more blue stickers than red stickers at first
= 10 u - 9 u
= 1 u
= 1 x 18
= 18

(c)
Number of blue stickers given away
= 10 u - 6 u
= 4 u
= 4 x 18
= 72

Answer(s): (a) 108; (b) 18; (c) 72