Adam has 95 stickers.
After
23 of the red stickers and
37 of the green stickers are given away,
there is an equal number of red and green stickers left.
- How many red stickers are there in the end?
- How many more red stickers are there than green stickers at first?
- How many green stickers are given away?
|
Red |
Green |
Total |
Before |
3 x 4 = 12 u |
7 x 1 = 7 u |
95 |
Change |
- 2 x 4 = - 8 u |
- 3 x 1 = - 3 u |
|
After |
1 x 4 = 4 u |
4 x 1 = 4 u |
|
(a)
Fraction of the red stickers left
= 1 -
23 =
13 Fraction of the green stickers left
= 1 -
37 =
47 Number of red stickers and green stickers left is the same.
Make the number of red stickers and green stickers left the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Total number of stickers
= 12 u + 7 u
= 19 u
19 u = 95
1 u = 95 ÷ 19 = 5
Number of red stickers in the end
= 4 u
= 4 x 5
= 20
(b)
Number of more red stickers than green stickers at first
= 12 u - 7 u
= 5 u
= 5 x 5
= 25
(c)
Number of green stickers given away
= 7 u - 4 u
= 3 u
= 3 x 5
= 15
Answer(s): (a) 20; (b) 25; (c) 15