Adam has 209 stickers.
After ¹₃ of the blue stickers and
²₅ of the green stickers are given away,
there is an equal number of blue and green stickers left.

1. How many blue stickers are there in the end?
2. How many more green stickers are there than blue stickers at first?
3. How many green stickers are given away?

	Blue	Green	Total
Before	3 x 3 = 9 u	5 x 2 = 10 u	209
Change	- 1 x 3 = - 3 u	- 2 x 2 = - 4 u
After	2 x 3 = 6 u	3 x 2 = 6 u

(a)
Fraction of the blue stickers left
= 1 - ¹₃
= ²₃

Fraction of the green stickers left
= 1 - ²₅
= ³₅

Number of blue stickers and green stickers left is the same.
Make the number of blue stickers and green stickers left the same using the LCM of 2 and 3.
LCM of 2 and 3 = 6

Total number of stickers
= 9 u + 10 u
= 19 u

19 u = 209

1 u = 209 ÷ 19 = 11

Number of blue stickers in the end
= 6 u
= 6 x 11
= 66

(b)
Number of more green stickers than blue stickers at first
= 10 u - 9 u
= 1 u
= 1 x 11
= 11

(c)
Number of green stickers given away
= 10 u - 6 u
= 4 u
= 4 x 11
= 44

Answer(s): (a) 66; (b) 11; (c) 44