Adam has 308 stickers.
After ²₃ of the red stickers and
³₅ of the green stickers are given away,
there is an equal number of red and green stickers left.

1. How many red stickers are there in the end?
2. How many more red stickers are there than green stickers at first?
3. How many green stickers are given away?

	Red	Green	Total
Before	3 x 2 = 6 u	5 x 1 = 5 u	308
Change	- 2 x 2 = - 4 u	- 3 x 1 = - 3 u
After	1 x 2 = 2 u	2 x 1 = 2 u

(a)
Fraction of the red stickers left
= 1 - ²₃
= ¹₃

Fraction of the green stickers left
= 1 - ³₅
= ²₅

Number of red stickers and green stickers left is the same.
Make the number of red stickers and green stickers left the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2

Total number of stickers
= 6 u + 5 u
= 11 u

11 u = 308

1 u = 308 ÷ 11 = 28

Number of red stickers in the end
= 2 u
= 2 x 28
= 56

(b)
Number of more red stickers than green stickers at first
= 6 u - 5 u
= 1 u
= 1 x 28
= 28

(c)
Number of green stickers given away
= 5 u - 2 u
= 3 u
= 3 x 28
= 84

Answer(s): (a) 56; (b) 28; (c) 84