Adam has 28 stickers.
After
23 of the blue stickers and
25 of the green stickers are given away,
there is an equal number of blue and green stickers left.
- How many blue stickers are there in the end?
- How many more blue stickers are there than green stickers at first?
- How many green stickers are given away?
|
Blue |
Green |
Total |
Before |
3 x 3 = 9 u |
5 x 1 = 5 u |
28 |
Change |
- 2 x 3 = - 6 u |
- 2 x 1 = - 2 u |
|
After |
1 x 3 = 3 u |
3 x 1 = 3 u |
|
(a)
Fraction of the blue stickers left
= 1 -
23 =
13 Fraction of the green stickers left
= 1 -
25 =
35 Number of blue stickers and green stickers left is the same.
Make the number of blue stickers and green stickers left the same using the LCM of 1 and 3.
LCM of 1 and 3 = 3
Total number of stickers
= 9 u + 5 u
= 14 u
14 u = 28
1 u = 28 ÷ 14 = 2
Number of blue stickers in the end
= 3 u
= 3 x 2
= 6
(b)
Number of more blue stickers than green stickers at first
= 9 u - 5 u
= 4 u
= 4 x 2
= 8
(c)
Number of green stickers given away
= 5 u - 3 u
= 2 u
= 2 x 2
= 4
Answer(s): (a) 6; (b) 8; (c) 4