Adam has 399 stickers.
After ¹₃ of the green stickers and
²₅ of the blue stickers are given away,
there is an equal number of green and blue stickers left.

1. How many green stickers are there in the end?
2. How many more blue stickers are there than green stickers at first?
3. How many blue stickers are given away?

	Green	Blue	Total
Before	3 x 3 = 9 u	5 x 2 = 10 u	399
Change	- 1 x 3 = - 3 u	- 2 x 2 = - 4 u
After	2 x 3 = 6 u	3 x 2 = 6 u

(a)
Fraction of the green stickers left
= 1 - ¹₃
= ²₃

Fraction of the blue stickers left
= 1 - ²₅
= ³₅

Number of green stickers and blue stickers left is the same.
Make the number of green stickers and blue stickers left the same using the LCM of 2 and 3.
LCM of 2 and 3 = 6

Total number of stickers
= 9 u + 10 u
= 19 u

19 u = 399

1 u = 399 ÷ 19 = 21

Number of green stickers in the end
= 6 u
= 6 x 21
= 126

(b)
Number of more blue stickers than green stickers at first
= 10 u - 9 u
= 1 u
= 1 x 21
= 21

(c)
Number of blue stickers given away
= 10 u - 6 u
= 4 u
= 4 x 21
= 84

Answer(s): (a) 126; (b) 21; (c) 84