Adam has 286 stickers.
After ²₃ of the red stickers and
²₇ of the blue stickers are given away,
there is an equal number of red and blue stickers left.

1. How many red stickers are there in the end?
2. How many more red stickers are there than blue stickers at first?
3. How many blue stickers are given away?

	Red	Blue	Total
Before	3 x 5 = 15 u	7 x 1 = 7 u	286
Change	- 2 x 5 = - 10 u	- 2 x 1 = - 2 u
After	1 x 5 = 5 u	5 x 1 = 5 u

(a)
Fraction of the red stickers left
= 1 - ²₃
= ¹₃

Fraction of the blue stickers left
= 1 - ²₇
= ⁵₇

Number of red stickers and blue stickers left is the same.
Make the number of red stickers and blue stickers left the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5

Total number of stickers
= 15 u + 7 u
= 22 u

22 u = 286

1 u = 286 ÷ 22 = 13

Number of red stickers in the end
= 5 u
= 5 x 13
= 65

(b)
Number of more red stickers than blue stickers at first
= 15 u - 7 u
= 8 u
= 8 x 13
= 104

(c)
Number of blue stickers given away
= 7 u - 5 u
= 2 u
= 2 x 13
= 26

Answer(s): (a) 65; (b) 104; (c) 26