Adam has 220 stickers.
After
23 of the green stickers and
27 of the blue stickers are given away,
there is an equal number of green and blue stickers left.
- How many green stickers are there in the end?
- How many more green stickers are there than blue stickers at first?
- How many blue stickers are given away?
|
Green |
Blue |
Total |
Before |
3 x 5 = 15 u |
7 x 1 = 7 u |
220 |
Change |
- 2 x 5 = - 10 u |
- 2 x 1 = - 2 u |
|
After |
1 x 5 = 5 u |
5 x 1 = 5 u |
|
(a)
Fraction of the green stickers left
= 1 -
23 =
13 Fraction of the blue stickers left
= 1 -
27 =
57 Number of green stickers and blue stickers left is the same.
Make the number of green stickers and blue stickers left the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
Total number of stickers
= 15 u + 7 u
= 22 u
22 u = 220
1 u = 220 ÷ 22 = 10
Number of green stickers in the end
= 5 u
= 5 x 10
= 50
(b)
Number of more green stickers than blue stickers at first
= 15 u - 7 u
= 8 u
= 8 x 10
= 80
(c)
Number of blue stickers given away
= 7 u - 5 u
= 2 u
= 2 x 10
= 20
Answer(s): (a) 50; (b) 80; (c) 20