Adam has 143 stickers.
After ²₃ of the green stickers and
³₅ of the blue stickers are given away,
there is an equal number of green and blue stickers left.

1. How many green stickers are there in the end?
2. How many more green stickers are there than blue stickers at first?
3. How many blue stickers are given away?

	Green	Blue	Total
Before	3 x 2 = 6 u	5 x 1 = 5 u	143
Change	- 2 x 2 = - 4 u	- 3 x 1 = - 3 u
After	1 x 2 = 2 u	2 x 1 = 2 u

(a)
Fraction of the green stickers left
= 1 - ²₃
= ¹₃

Fraction of the blue stickers left
= 1 - ³₅
= ²₅

Number of green stickers and blue stickers left is the same.
Make the number of green stickers and blue stickers left the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2

Total number of stickers
= 6 u + 5 u
= 11 u

11 u = 143

1 u = 143 ÷ 11 = 13

Number of green stickers in the end
= 2 u
= 2 x 13
= 26

(b)
Number of more green stickers than blue stickers at first
= 6 u - 5 u
= 1 u
= 1 x 13
= 13

(c)
Number of blue stickers given away
= 5 u - 2 u
= 3 u
= 3 x 13
= 39

Answer(s): (a) 26; (b) 13; (c) 39