Bryan and Adam have a total of $88.
Bryan spends
12 of his money and
Adam spends
17 of his money.
They spend $24 altogether.
- How much does Bryan have at first?
- How much does Adam have in the end?
|
Bryan |
Adam |
Before |
2 u |
7 p |
Change |
- 1 u |
- 1 p |
After |
1 u |
6 p |
(a)
Amount that Bryan has at first = 2 u
Amount that Adam has at first = 7 p
Total amount that they have = 2 u + 7 p = 88 --- (1)
Total amount that they spend = 1 u + 1 p = 24 --- (2)
(2)
x 7 7 u + 7 p = 168 --- (3)
(3) - (1)
(7 u + 7 p) - (2 u + 7 p) = 168 - 88
7 u + 7 p - 2 u - 7 p = 168 - 88
7 u - 2 u + 7 p - 7 p = 80
7 u - 2 u = 80
5 u = 80
1 u = 80 ÷ 5 = 16
Substitute 1 u = 16 into (1).
2 u + 7 p = 88
2 x 16 + 7 p = 88
32 + 7 p = 88
7 p = 88 - 32 = 56
1 p = 56 ÷ 7 = 8
Amount that Bryan has at first
= 2 u
= 2 x 16
= $32
(b)
Amount that Adam has in the end
= 7 p - 1 p
= 6 p
= 6 x 8
= $48
Answer(s): (a) $32; (b) $48