Adam has some paint.
He uses
45 of it to paint 6 tables and 5 chairs.
The amount of paint needed to paint a chair is 2 times that of a table.
- How many tables can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Tables |
Chairs |
Number |
6 |
5 |
Value |
1 u |
2 u |
Total value |
6 u |
10 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 chair = 2 u
Paint needed for 6 tables and 5 chairs
= 6 x 1 u x 5 x 2 u
= 6 u + 10 u
= 16 u
45 of the paint = 16 u
15 of the paint = 16 u ÷ 4 = 4 u
Fraction of the remaining paint left
= 1 -
45=
15 15 of the paint = 1 x 4 u = 4 u
Remaining paint left = 4 u
Number of tables that Adam can paint with the remaining paint
= 4 u ÷ 1 u
= 4
(b)
Number of chairs that Adam can paint with the remaining paint
= 4 u ÷ 2 u
= 2
Answer(s): (a) 4; (b) 2