Adam has some paint.
He uses
23 of it to paint 5 gates and 7 chairs.
The amount of paint needed to paint a chair is 5 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
5 |
7 |
Value |
1 u |
5 u |
Total value |
5 u |
35 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 5 u
Paint needed for 5 gates and 7 chairs
= 5 x 1 u x 7 x 5 u
= 5 u + 35 u
= 40 u
23 of the paint = 40 u
13 of the paint = 40 u ÷ 2 = 20 u
Fraction of the remaining paint left
= 1 -
23=
13 13 of the paint = 1 x 20 u = 20 u
Remaining paint left = 20 u
Number of gates that Adam can paint with the remaining paint
= 20 u ÷ 1 u
= 20
(b)
Number of chairs that Adam can paint with the remaining paint
= 20 u ÷ 5 u
= 4
Answer(s): (a) 20; (b) 4