Adam has some paint.
He uses
311 of it to paint 2 gates and 5 doors.
The amount of paint needed to paint a door is 2 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Gates |
Doors |
Number |
2 |
5 |
Value |
1 u |
2 u |
Total value |
2 u |
10 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 door = 2 u
Paint needed for 2 gates and 5 doors
= 2 x 1 u x 5 x 2 u
= 2 u + 10 u
= 12 u
311 of the paint = 12 u
111 of the paint = 12 u ÷ 3 = 4 u
Fraction of the remaining paint left
= 1 -
311=
811 811 of the paint = 8 x 4 u = 32 u
Remaining paint left = 32 u
Number of gates that Adam can paint with the remaining paint
= 32 u ÷ 1 u
= 32
(b)
Number of doors that Adam can paint with the remaining paint
= 32 u ÷ 2 u
= 16
Answer(s): (a) 32; (b) 16