Adam has some paint.
He uses
35 of it to paint 2 gates and 10 chairs.
The amount of paint needed to paint a chair is 4 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
2 |
10 |
Value |
1 u |
4 u |
Total value |
2 u |
40 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 4 u
Paint needed for 2 gates and 10 chairs
= 2 x 1 u x 10 x 4 u
= 2 u + 40 u
= 42 u
35 of the paint = 42 u
15 of the paint = 42 u ÷ 3 = 14 u
Fraction of the remaining paint left
= 1 -
35=
25 25 of the paint = 2 x 14 u = 28 u
Remaining paint left = 28 u
Number of gates that Adam can paint with the remaining paint
= 28 u ÷ 1 u
= 28
(b)
Number of chairs that Adam can paint with the remaining paint
= 28 u ÷ 4 u
= 7
Answer(s): (a) 28; (b) 7