Adam has some paint.
He uses
811 of it to paint 4 gates and 6 chairs.
The amount of paint needed to paint a chair is 2 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
4 |
6 |
Value |
1 u |
2 u |
Total value |
4 u |
12 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 2 u
Paint needed for 4 gates and 6 chairs
= 4 x 1 u x 6 x 2 u
= 4 u + 12 u
= 16 u
811 of the paint = 16 u
111 of the paint = 16 u ÷ 8 = 2 u
Fraction of the remaining paint left
= 1 -
811=
311 311 of the paint = 3 x 2 u = 6 u
Remaining paint left = 6 u
Number of gates that Adam can paint with the remaining paint
= 6 u ÷ 1 u
= 6
(b)
Number of chairs that Adam can paint with the remaining paint
= 6 u ÷ 2 u
= 3
Answer(s): (a) 6; (b) 3