Adam has some paint.
He uses
58 of it to paint 6 gates and 8 chairs.
The amount of paint needed to paint a chair is 3 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
6 |
8 |
Value |
1 u |
3 u |
Total value |
6 u |
24 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 6 gates and 8 chairs
= 6 x 1 u x 8 x 3 u
= 6 u + 24 u
= 30 u
58 of the paint = 30 u
18 of the paint = 30 u ÷ 5 = 6 u
Fraction of the remaining paint left
= 1 -
58=
38 38 of the paint = 3 x 6 u = 18 u
Remaining paint left = 18 u
Number of gates that Adam can paint with the remaining paint
= 18 u ÷ 1 u
= 18
(b)
Number of chairs that Adam can paint with the remaining paint
= 18 u ÷ 3 u
= 6
Answer(s): (a) 18; (b) 6