Adam has some paint.
He uses
34 of it to paint 3 chairs and 2 tables.
The amount of paint needed to paint a table is 3 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Chairs |
Tables |
Number |
3 |
2 |
Value |
1 u |
3 u |
Total value |
3 u |
6 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 table = 3 u
Paint needed for 3 chairs and 2 tables
= 3 x 1 u x 2 x 3 u
= 3 u + 6 u
= 9 u
34 of the paint = 9 u
14 of the paint = 9 u ÷ 3 = 3 u
Fraction of the remaining paint left
= 1 -
34=
14 14 of the paint = 1 x 3 u = 3 u
Remaining paint left = 3 u
Number of chairs that Adam can paint with the remaining paint
= 3 u ÷ 1 u
= 3
(b)
Number of tables that Adam can paint with the remaining paint
= 3 u ÷ 3 u
= 1
Answer(s): (a) 3; (b) 1