Adam has some paint.
He uses
38 of it to paint 6 gates and 7 chairs.
The amount of paint needed to paint a chair is 3 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
6 |
7 |
Value |
1 u |
3 u |
Total value |
6 u |
21 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 3 u
Paint needed for 6 gates and 7 chairs
= 6 x 1 u x 7 x 3 u
= 6 u + 21 u
= 27 u
38 of the paint = 27 u
18 of the paint = 27 u ÷ 3 = 9 u
Fraction of the remaining paint left
= 1 -
38=
58 58 of the paint = 5 x 9 u = 45 u
Remaining paint left = 45 u
Number of gates that Adam can paint with the remaining paint
= 45 u ÷ 1 u
= 45
(b)
Number of chairs that Adam can paint with the remaining paint
= 45 u ÷ 3 u
= 15
Answer(s): (a) 45; (b) 15