Adam has some paint.
He uses
512 of it to paint 10 tables and 8 doors.
The amount of paint needed to paint a door is 5 times that of a table.
- How many tables can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Tables |
Doors |
Number |
10 |
8 |
Value |
1 u |
5 u |
Total value |
10 u |
40 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 door = 5 u
Paint needed for 10 tables and 8 doors
= 10 x 1 u x 8 x 5 u
= 10 u + 40 u
= 50 u
512 of the paint = 50 u
112 of the paint = 50 u ÷ 5 = 10 u
Fraction of the remaining paint left
= 1 -
512=
712 712 of the paint = 7 x 10 u = 70 u
Remaining paint left = 70 u
Number of tables that Adam can paint with the remaining paint
= 70 u ÷ 1 u
= 70
(b)
Number of doors that Adam can paint with the remaining paint
= 70 u ÷ 5 u
= 14
Answer(s): (a) 70; (b) 14