Adam has some paint.
He uses
511 of it to paint 10 chairs and 5 doors.
The amount of paint needed to paint a door is 2 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Chairs |
Doors |
Number |
10 |
5 |
Value |
1 u |
2 u |
Total value |
10 u |
10 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 door = 2 u
Paint needed for 10 chairs and 5 doors
= 10 x 1 u x 5 x 2 u
= 10 u + 10 u
= 20 u
511 of the paint = 20 u
111 of the paint = 20 u ÷ 5 = 4 u
Fraction of the remaining paint left
= 1 -
511=
611 611 of the paint = 6 x 4 u = 24 u
Remaining paint left = 24 u
Number of chairs that Adam can paint with the remaining paint
= 24 u ÷ 1 u
= 24
(b)
Number of doors that Adam can paint with the remaining paint
= 24 u ÷ 2 u
= 12
Answer(s): (a) 24; (b) 12