Adam has some paint.
He uses
711 of it to paint 6 chairs and 2 doors.
The amount of paint needed to paint a door is 4 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Chairs |
Doors |
Number |
6 |
2 |
Value |
1 u |
4 u |
Total value |
6 u |
8 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 door = 4 u
Paint needed for 6 chairs and 2 doors
= 6 x 1 u x 2 x 4 u
= 6 u + 8 u
= 14 u
711 of the paint = 14 u
111 of the paint = 14 u ÷ 7 = 2 u
Fraction of the remaining paint left
= 1 -
711=
411 411 of the paint = 4 x 2 u = 8 u
Remaining paint left = 8 u
Number of chairs that Adam can paint with the remaining paint
= 8 u ÷ 1 u
= 8
(b)
Number of doors that Adam can paint with the remaining paint
= 8 u ÷ 4 u
= 2
Answer(s): (a) 8; (b) 2