Adam has some paint.
He uses
811 of it to paint 5 chairs and 9 gates.
The amount of paint needed to paint a gate is 3 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many gates can he paint using the remaining paint?
|
Chairs |
Gates |
Number |
5 |
9 |
Value |
1 u |
3 u |
Total value |
5 u |
27 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 gate = 3 u
Paint needed for 5 chairs and 9 gates
= 5 x 1 u x 9 x 3 u
= 5 u + 27 u
= 32 u
811 of the paint = 32 u
111 of the paint = 32 u ÷ 8 = 4 u
Fraction of the remaining paint left
= 1 -
811=
311 311 of the paint = 3 x 4 u = 12 u
Remaining paint left = 12 u
Number of chairs that Adam can paint with the remaining paint
= 12 u ÷ 1 u
= 12
(b)
Number of gates that Adam can paint with the remaining paint
= 12 u ÷ 3 u
= 4
Answer(s): (a) 12; (b) 4