Adam has some paint.
He uses
59 of it to paint 9 chairs and 4 tables.
The amount of paint needed to paint a table is 4 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many tables can he paint using the remaining paint?
|
Chairs |
Tables |
Number |
9 |
4 |
Value |
1 u |
4 u |
Total value |
9 u |
16 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 table = 4 u
Paint needed for 9 chairs and 4 tables
= 9 x 1 u x 4 x 4 u
= 9 u + 16 u
= 25 u
59 of the paint = 25 u
19 of the paint = 25 u ÷ 5 = 5 u
Fraction of the remaining paint left
= 1 -
59=
49 49 of the paint = 4 x 5 u = 20 u
Remaining paint left = 20 u
Number of chairs that Adam can paint with the remaining paint
= 20 u ÷ 1 u
= 20
(b)
Number of tables that Adam can paint with the remaining paint
= 20 u ÷ 4 u
= 5
Answer(s): (a) 20; (b) 5