Adam has some paint.
He uses
311 of it to paint 9 gates and 6 chairs.
The amount of paint needed to paint a chair is 4 times that of a gate.
- How many gates can he paint using the remaining paint?
- How many chairs can he paint using the remaining paint?
|
Gates |
Chairs |
Number |
9 |
6 |
Value |
1 u |
4 u |
Total value |
9 u |
24 u |
(a)
Paint needed for 1 gate = 1 u
Paint needed for 1 chair = 4 u
Paint needed for 9 gates and 6 chairs
= 9 x 1 u x 6 x 4 u
= 9 u + 24 u
= 33 u
311 of the paint = 33 u
111 of the paint = 33 u ÷ 3 = 11 u
Fraction of the remaining paint left
= 1 -
311=
811 811 of the paint = 8 x 11 u = 88 u
Remaining paint left = 88 u
Number of gates that Adam can paint with the remaining paint
= 88 u ÷ 1 u
= 88
(b)
Number of chairs that Adam can paint with the remaining paint
= 88 u ÷ 4 u
= 22
Answer(s): (a) 88; (b) 22