Adam has some paint.
He uses
35 of it to paint 2 chairs and 7 doors.
The amount of paint needed to paint a door is 4 times that of a chair.
- How many chairs can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Chairs |
Doors |
Number |
2 |
7 |
Value |
1 u |
4 u |
Total value |
2 u |
28 u |
(a)
Paint needed for 1 chair = 1 u
Paint needed for 1 door = 4 u
Paint needed for 2 chairs and 7 doors
= 2 x 1 u x 7 x 4 u
= 2 u + 28 u
= 30 u
35 of the paint = 30 u
15 of the paint = 30 u ÷ 3 = 10 u
Fraction of the remaining paint left
= 1 -
35=
25 25 of the paint = 2 x 10 u = 20 u
Remaining paint left = 20 u
Number of chairs that Adam can paint with the remaining paint
= 20 u ÷ 1 u
= 20
(b)
Number of doors that Adam can paint with the remaining paint
= 20 u ÷ 4 u
= 5
Answer(s): (a) 20; (b) 5