Adam has some paint.
He uses
37 of it to paint 6 tables and 4 doors.
The amount of paint needed to paint a door is 3 times that of a table.
- How many tables can he paint using the remaining paint?
- How many doors can he paint using the remaining paint?
|
Tables |
Doors |
Number |
6 |
4 |
Value |
1 u |
3 u |
Total value |
6 u |
12 u |
(a)
Paint needed for 1 table = 1 u
Paint needed for 1 door = 3 u
Paint needed for 6 tables and 4 doors
= 6 x 1 u x 4 x 3 u
= 6 u + 12 u
= 18 u
37 of the paint = 18 u
17 of the paint = 18 u ÷ 3 = 6 u
Fraction of the remaining paint left
= 1 -
37=
47 47 of the paint = 4 x 6 u = 24 u
Remaining paint left = 24 u
Number of tables that Adam can paint with the remaining paint
= 24 u ÷ 1 u
= 24
(b)
Number of doors that Adam can paint with the remaining paint
= 24 u ÷ 3 u
= 8
Answer(s): (a) 24; (b) 8